Category: Engineering maths

Net 33

CBSE NET July 2016 PAPER II Q. How many committees of five people can be chosen from 20 men and 12 women such that each committee contains at least three women? (A) 75240(B) 52492(C) 41800(D) 9900 Ans :- (A) Explanation:- At least 3 women means, minimum 3 women should be in 5 people group. So, […]

Net 30

CBSE NET July 2016 PAPER II Q. The Simplified form of a Boolean equation (AB’+AB’C+AC)(A’C’ +B’) is (A) 0 (B) 1 (C) -1 (D) -2 Ans :- (A) Explanation:- (AB’+AB’C+AC)(A’C’ +B’) On simplifying above equation, (AB’A’C’+AB’CA’C’+ACA’C’+AB’B’+AB’CB’+ACB’) (0+0+0+AB’+AB’C+ACB’) Because multiplication of element with its complement is 0. (AB’+AB’C) AB’(1+C) AB’

Net 9

CBSE NET JUNE 2012 PAPER III If two fuzzy sets A and B are given with membership functions μA(x) = {0.2, 0.4, 0.8, 0.5, 0.1} μB(x) = {0.1, 0.3, 0.6, 0.3, 0.2} Then the value of μ – will be A∩B(A) {0.9, 0.7, 0.4, 0.8, 0.9}(B) {0.2, 0.4, 0.8, 0.5, 0.2}(C) {0.1, 0.3, 0.6, 0.3, […]

Net 8

CBSE NET JANUARY 2017 PAPER II The hexadecimal equivalent of the octal number 2357 is: (1) 2EE (2) 2FF (3) 4EF (4) 4FE Ans: (3) Explanation: (2357)8 to binary = 010 011 101 111. Each digit is broken into 3 binary bits. Now regroup these bits into groups of 4 to convert to hexadecimal.= 0100 1110 […]

Net 7

CBSE NET JANUARY 2017 PAPER II Convert the octal number 0.4051 into its equivalent decimal number. (1) 0.5100098 (2) 0.2096 (3) 0.52 (4) 0.4192 Ans: (1) Explanation: (0.4051)8 = 4x(1/8)+0x(1/64)+5x(1/512)+1x(1/4096) = 0.5100098 So correct option is 1.

Net 6

CBSE NET JANUARY 2017 PAPER II How many multiples of 6 are there between the following pairs of numbers?0 to 100 and     -6 to 34 (1) 16 and 6 (2) 17 and 6 (3) 17 and 7 (4) 16 and 7 Ans: (3) Explanation: This question can be solved using simple logic too. Number of […]

Net 5

CBSE NET JANUARY 2017 PAPER II The functions mapping R into R are defined as: f(x) = x3-4x, g(x)=1/(x2+1) and h(x)=x4Then find the value of the following composite functions: hog(x) and hogof(x) (1) (x2+1)4 and [(x3-4x)2+1]4(2) (x2+1)4 and [(x3-4x)2+1]- 4(3) (x2+1)- 4 and [(x3-4x)2+1]4(4) (x2+1)‑ 4 and [(x3-4x)2+1]- 4 Ans:​ (4) Explanation: hog(x)​ = h(1/(x2+1))= […]