Find a real root of the equation x= e ^ (-x) using newton Raphson method.(R.G.P.V May 2019)
Solution Let,F(x) = x – e ^ (-x)Now put x=0: 0 – e ^ (-0) = -1Now put x=1: 1 – e^ (-1) = 0.6321Thus … Read more
Solution Let,F(x) = x – e ^ (-x)Now put x=0: 0 – e ^ (-0) = -1Now put x=1: 1 – e^ (-1) = 0.6321Thus … Read more
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Solution: Let, F(x)= x^4-x-10 Here, f’(Xn)= 4x^3-1 According to the question, it will be given x0= 2.. X0+1= x0- (x0^(4)-x0-10)/(4×0^(3)-1) X1=x0-(x0^(4)-x0-10)/(4×0^3-1) Put the value … Read more
Solution: Let, F(x)=x^3-4x-9=0 Now, Put x=0:- 0^(3)-4*0-9= -9 (-ve) Put x=1:- 1^(3)-4*1-9= -13 (-ve) Put x=2:- 2^(3)-4*2-9= -9 (-ve) Put x=3:- 3^(3)-4*3-9= 6 (+v) … Read more
Solution: Let, F(x)=x^3-2x-5=0 Now, Put x=0:- 0^(3)-2*0-5= -5 (-ve) Put x=1:- 1^(3)-2*1-5= -6 (-ve) Put x=2:- 2^(3)-2*2-5= -1 (-ve) Put x=3:- 3^(3)-2*3-5= 16 (+v) … Read more