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Net 8

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By Team EasyExamNotes

CBSE NET JANUARY 2017 PAPER II

The hexadecimal equivalent of the octal number 2357 is:

(1) 2EE

(2) 2FF

(3) 4EF

(4) 4FE

Ans: (3)

Explanation:

(2357)8 to binary = 010 011 101 111. Each digit is broken into 3 binary bits.

Now regroup these bits into groups of 4 to convert to hexadecimal.
= 0100 1110 1111
= 4EF

So correct answer is 3.

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