**CBSE NET**

**Q.**Consider an array A[20, 10], assume 4 words per memory cell and the base address of array A is 100. What is the address of A[11, 5] ? Assume row major storage.

(A) 560

(B) 565

(C) 570

(D) 575

**Ans:**

**(A)**

**Explanation:**

Formula for calculating address of element in row major and column major order is as shown in below image.

Where,

B=Base address, w=element size, Nc=number of column, Nr=number of row, Lc=column lower bound, Lr=row lower bound.

**Using formula of row major,**

Address of (11,5) = 100+4(10(11-0)+(5-0))= 100+4(115)=

*560.*