C
#include <stdio.h>
int main() {
int n, i;
long long int fib1 = 0, fib2 = 1, fib3;
printf("Enter the number of terms: ");
scanf("%d", &n);
printf("Fibonacci Sequence: ");
// Special case for first two terms
if (n >= 1) {
printf("%lld ", fib1);
}
if (n >= 2) {
printf("%lld ", fib2);
}
// Generate and print the remaining terms
for (i = 3; i <= n; i++) {
fib3 = fib1 + fib2;
printf("%lld ", fib3);
fib1 = fib2;
fib2 = fib3;
}
printf("\n");
return 0;
}Explanation:
- In this program, we declare variables n and i. fib1 and fib2 are used to store the current and next terms in the Fibonacci sequence, respectively. fib3 is used to calculate the new term.
- The program asks the user to enter the number of terms they want to print (N).
- It then prints the first two terms (fib1 and fib2) separately.
- After that, it generates and prints the remaining terms using a for loop.
Output:
Output
Enter the number of terms: 9
Fibonacci Sequence: 0 1 1 2 3 5 8 13 21 Why long long int in above program ?
- This program assumes that N is a positive integer.
- It uses the long long int data type to handle large Fibonacci numbers.