Assuming that all registers initially contain 0, what is the value of R1after the following instruction sequence is executed : MOV R1, # 6 MOV R2, # 5 ADD R3, R1, R1 SUB R1, R3, R2 MUL R3, R1, R1.

MOV R1, #6 {Directly move 6 to the register R1}

MOV R2, #5 {Take another register in which directly move 5 into it}

ADD R3, R1, R1 {Value stored in R1 added to R1 again and then stored in R3} Thus, R3 has a value of 12.

SUB R1, R3, R2 {Value of R2 is subtracted from R3and move into the R1}Thus R1 has a value of = R3– R2= 12 – 5 = 7

MUL R3, R1, R1{Multiply R1with R1and store into R3}
Thus, the final execution of this statement will give 49 and R1 contains 7 as value stored in it.